Class 11 Physics · Chapter 8 NotesMechanical Properties of Solids

Study Class 11 Physics Chapter 8 Mechanical Properties of Solids. Learn stress, strain, Hooke's law, Young's modulus, shear modulus, bulk modulus, and more.

4 topics5 sample MCQs5 practice questions
Chapter contents

Chapter summary

In this chapter, you will learn how solid bodies respond when forces are applied to them. A rigid body is only an idealisation; real solids can be stretched, compressed, bent, or twisted. The property by which a body regains its original shape and size after the deforming force is removed is called elasticity, while the property of permanent deformation is called plasticity. You will study stress and strain, Hooke's law, the stress-strain curve, and the three elastic moduli: Young's modulus, shear modulus, and bulk modulus. You will also learn about Poisson's ratio, elastic potential energy stored in a stretched wire, and how these ideas are applied in engineering and everyday life, such as in the design of beams, columns, and cranes.

What you'll learn

1Define stress and strain and distinguish between tensile, compressive, shearing, and hydraulic stress.
2State Hooke's law and explain the modulus of elasticity.
3Interpret a typical stress-strain curve and identify the proportional limit, yield point, ultimate tensile strength, and fracture point.
4Define Young's modulus, shear modulus, and bulk modulus, and write their formulas.
5Explain Poisson's ratio and calculate lateral strain from longitudinal strain.
6Derive and use the expression for elastic potential energy stored in a stretched wire.
7Apply the concepts of elastic moduli to real-life situations such as the design of beams, columns, and cranes.

Chapter at a glance

01Stress, Strain, and Elastic Behavior
02Young's Modulus, Bulk Modulus, and Shear Modulus
03Poisson's Ratio and Elastic Energy
04Stress-Strain Curve and Elastic Limits

Detailed chapter notes

01

Stress and Strain

When external forces deform a body, internal restoring forces develop. The restoring force per unit area is called stress. Its SI unit is N m⁻² or pascal (Pa). Strain is the fractional change in dimension. There are three types of stress: tensile or compressive (longitudinal) stress, shearing stress, and hydraulic stress. Longitudinal strain is the change in length divided by original length. Shearing strain is the ratio of relative displacement of faces to the perpendicular distance, approximately equal to the angle θ. Volume strain is the change in volume divided by original volume. Strain has no units.

  • Stress = F/A
  • Longitudinal strain = ΔL/L
  • Shearing strain = Δx/L = tan θ ≈ θ
  • Volume strain = ΔV/V
02

Hooke's Law

For small deformations, stress is directly proportional to strain. This is known as Hooke's law. The constant of proportionality is called the modulus of elasticity. Hooke's law is an empirical law and is valid for many materials within the elastic limit. However, some materials like elastomers do not obey Hooke's law over most of the region. The modulus of elasticity is a characteristic of the material and is independent of the dimensions of the body.

  • Stress ∝ Strain
  • Stress = k × Strain, where k is modulus of elasticity
03

Stress-Strain Curve

A typical stress-strain curve for a metal shows different regions. From O to A, stress is proportional to strain (Hooke's law). Point A is the proportional limit. From A to B, stress and strain are not proportional, but the body still returns to its original shape when the load is removed. Point B is the yield point or elastic limit, and the corresponding stress is the yield strength. Beyond B, plastic deformation occurs. Point D is the ultimate tensile strength, and fracture occurs at point E. If D and E are close, the material is brittle; if they are far apart, it is ductile.

  • Proportional limitpoint A
  • Yield point (elastic limit)point B
  • Ultimate tensile strengthpoint D
  • Fracture pointpoint E
04

Young's Modulus

Young's modulus (Y) is the ratio of tensile (or compressive) stress to longitudinal strain. It is a measure of the stiffness of a material. A material with a large Young's modulus requires a large force to produce a small change in length. For example, steel has a larger Young's modulus than copper, brass, and aluminium, so steel is more elastic in the sense that it stretches less for a given load. Young's modulus is relevant only for solids. Its SI unit is N m⁻² or Pa.

  • Y = (F/A) / (ΔL/L) = (F × L) / (A × ΔL)
  • UnitN m⁻² or Pa
  • Steel is more elastic than copper, brass, and aluminium.
05

Shear Modulus

The ratio of shearing stress to shearing strain is called the shear modulus (G), also known as the modulus of rigidity. It is defined by G = (F/A) / θ, where θ is the angular deformation. Shear modulus is relevant only for solids because only solids have a definite shape. For most materials, G is less than Y, and approximately G ≈ Y/3. The SI unit is N m⁻² or Pa.

  • G = (F/A) / θ = (F × L) / (A × Δx)
  • UnitN m⁻² or Pa
  • G ≈ Y/3 for most materials
06

Bulk Modulus

The ratio of hydraulic stress to volume strain is called the bulk modulus (B). It is defined as B = –p / (ΔV/V), where p is the pressure and ΔV/V is the volume strain. The negative sign indicates that volume decreases with increase in pressure. The reciprocal of bulk modulus is compressibility (k). Bulk modulus is relevant for solids, liquids, and gases. Solids have the largest bulk modulus, gases the smallest. For example, the bulk modulus of steel is about 160 GPa, while that of air at STP is about 1.0 × 10⁻⁴ GPa.

  • B = –p / (ΔV/V)
  • Compressibility k = 1/B
  • UnitN m⁻² or Pa
07

Poisson's Ratio

When a wire is stretched, its length increases and its diameter decreases. The strain perpendicular to the applied force is called lateral strain, and the strain along the force is longitudinal strain. Within the elastic limit, lateral strain is directly proportional to longitudinal strain. The ratio of lateral strain to longitudinal strain is called Poisson's ratio (σ). It is a pure number with no units. For steels, its value is between 0.28 and 0.30, and for aluminium alloys, it is about 0.33.

  • Poisson's ratio σ = (Δd/d) / (ΔL/L)
  • No units or dimensions
  • Typical valuessteel 0.28–0.30, aluminium alloys ~0.33
08

Elastic Potential Energy in a Stretched Wire

When a wire is stretched, work is done against inter-atomic forces. This work is stored as elastic potential energy. For a wire of length L and area A, stretched by a small amount l, the work done is W = ½ × Y × (l/L)² × A × L. This can also be written as W = ½ × stress × strain × volume of the wire. The elastic potential energy per unit volume is u = ½ × stress × strain.

  • W = ½ × Y × (strain)² × volume
  • u = ½ × stress × strain
09

Applications of Elastic Behaviour

Knowledge of elastic properties is essential in engineering design. For example, the thickness of a crane rope is determined by ensuring that the stress does not exceed the yield strength of the material. Beams used in bridges and buildings are often given an I-shaped cross-section to reduce bending and buckling while minimising weight. The maximum height of a mountain on Earth is limited by the elastic properties of rocks; if the shear stress at the base exceeds the elastic limit, rocks flow. These examples show how the concepts of stress, strain, and elastic moduli are used in real-world applications.

  • Crane rope thicknessA ≥ W/σ_y
  • Beam bendingδ = W l³ / (4 b d³ Y)
  • Mountain height limithρg = elastic limit of rock
Want the complete chapter resources?Topic notes, quizzes and flashcards for Mechanical Properties of Solids.
Explore full chapter →

Quick revision: key points

  • Stress is the restoring force per unit area; strain is the fractional change in dimension.
  • Hooke's law: stress ∝ strain, valid for small deformations.
  • Young's modulus Y = (F/A) / (ΔL/L) measures stiffness of solids.
  • Shear modulus G = (F/A) / θ measures resistance to shape change.
  • Bulk modulus B = –p / (ΔV/V) measures resistance to volume change.
  • Poisson's ratio = lateral strain / longitudinal strain.
  • Elastic potential energy per unit volume = ½ × stress × strain.
  • Stress-strain curve: proportional limit, yield point, ultimate tensile strength, fracture point.
  • Steel is more elastic than copper, brass, and aluminium because it has a larger Young's modulus.
  • Bulk modulus is relevant for solids, liquids, and gases; Young's and shear moduli only for solids.

Test yourself

Try each question first, then reveal the answer.

Question 01

Stress is defined as the ratio of applied force to the cross-sectional area. What are the SI units of stress?

  • ANewton per square meter (N/m²) or Pascal (Pa)
  • BNewton per meter (N/m)
  • CKilogram per square meter (kg/m²)
  • DJoule per square meter (J/m²)
Show answer
Answer: (A) Newton per square meter (N/m²) or Pascal (Pa)

Stress = Force/Area, so its SI unit is N/m², which is equivalent to Pascal (Pa). This is the standard unit used in mechanics.

Question 02

Young's modulus is defined as the ratio of stress to strain for which type of deformation?

  • ALongitudinal deformation
  • BVolumetric deformation
  • CShear deformation
  • DTorsional deformation
Show answer
Answer: (A) Longitudinal deformation

Young's modulus specifically measures the resistance of a material to longitudinal (tensile or compressive) deformation. It is defined as Y = (Longitudinal stress)/(Longitudinal strain).

Question 03

Poisson's ratio is defined as the ratio of

  • Alateral strain to longitudinal strain
  • Blongitudinal strain to lateral strain
  • Cstress to strain
  • DYoung's modulus to bulk modulus
Show answer
Answer: (A) lateral strain to longitudinal strain

Poisson's ratio (σ) is defined as the negative ratio of lateral (transverse) strain to longitudinal strain when a material is stressed uniaxially. It is a dimensionless quantity.

Question 04

What is stress defined as in the context of mechanical properties of solids?

  • AThe internal force per unit area acting on a material
  • BThe change in length of a material
  • CThe elastic potential energy stored in the material
  • DThe rate of change of strain with time
Show answer
Answer: (A) The internal force per unit area acting on a material

Stress is the internal restoring force per unit cross-sectional area. It is a measure of the intensity of internal forces acting within a material.

Question 05

Strain is a dimensionless quantity representing the deformation of a material. Which of the following correctly describes strain?

  • AStrain = Change in length / Original length
  • BStrain = Applied force / Young's modulus
  • CStrain = Stress × Elastic modulus
  • DStrain = Cross-sectional area / Applied force
Show answer
Answer: (A) Strain = Change in length / Original length

Strain is defined as the ratio of change in dimension to the original dimension. It is dimensionless and represents relative deformation.

Ready for more practice?Unlock the full quiz for this chapter.
Try more questions →

Sample questions and answers

Sample question3 marks

Q1. Define stress and strain. State Hooke's law for a deforming force.

Show model answer
Model answer

Stress is the restoring force per unit area developed inside a body when a deforming force is applied. Strain is the fractional change in dimension of the body. Hooke's law states that for small deformations, stress is directly proportional to strain.

Sample question3 marks

Q2. Define Young's modulus and write its expression. A steel wire of length 2 m and cross-sectional area 1 mm² is stretched by a force of 200 N. If Young's modulus of steel is 2 × 10¹¹ N/m², calculate the elongation of the wire.

Show model answer
Model answer

Young's modulus (Y) is the ratio of tensile stress to longitudinal strain within the elastic limit. Y = (F/A) / (ΔL/L) = (F × L) / (A × ΔL). Given F = 200 N, L = 2 m, A = 1 mm² = 1 × 10⁻⁶ m², Y = 2 × 10¹¹ N/m². Using ΔL = (F × L) / (Y × A) = (200 × 2) / (2 × 10¹¹ × 10⁻⁶) = 400 / (2 × 10⁵) = 2 × 10⁻³ m = 2 mm.

Sample question3 marks

Q3. Define Poisson's ratio. A wire of length 2 m and diameter 1 mm is stretched by a load, resulting in a longitudinal strain of 0.001. If the Poisson's ratio for the material is 0.3, calculate the change in diameter.

Show model answer
Model answer

Poisson's ratio is the ratio of lateral strain to longitudinal strain within the elastic limit. Given longitudinal strain = 0.001, Poisson's ratio = 0.3, so lateral strain = 0.3 × 0.001 = 3 × 10⁻⁴. Original diameter = 1 mm = 10⁻³ m, so change in diameter = lateral strain × original diameter = 3 × 10⁻⁴ × 10⁻³ = 3 × 10⁻⁷ m.

Sample question3 marks

Q4. Distinguish between Young's modulus and shear modulus. Give one example of each type of deformation.

Show model answer
Model answer

Young's modulus is the ratio of tensile or compressive stress to longitudinal strain, applicable when forces are perpendicular to the cross-section. Shear modulus is the ratio of shearing stress to shearing strain, applicable when forces are parallel to the faces. Example: stretching a wire (Young's modulus); twisting a cylinder (shear modulus).

Sample question3 marks

Q5. Define bulk modulus and compressibility. A solid sphere is subjected to a hydraulic pressure of 2 × 10⁶ Pa. If the bulk modulus of the material is 1 × 10¹⁰ Pa, calculate the fractional change in volume of the sphere.

Show model answer
Model answer

Bulk modulus (B) is the ratio of hydraulic stress (p) to volume strain (ΔV/V). B = -p/(ΔV/V). Compressibility (k) is the reciprocal of bulk modulus: k = 1/B. Given p = 2 × 10⁶ Pa, B = 1 × 10¹⁰ Pa. Fractional change in volume ΔV/V = p/B = (2 × 10⁶)/(1 × 10¹⁰) = 2 × 10⁻⁴.

Want more questions with answers?Get the full practice set for this chapter.
Get more practice — free →

Frequently asked questions

What is stress and what are its types?

Stress is the restoring force per unit area developed inside a body when an external deforming force is applied. Its SI unit is N m⁻² or pascal (Pa). There are three types: tensile or compressive stress (longitudinal), shearing stress, and hydraulic stress.

What is the difference between elastic and plastic deformation?

Elastic deformation is temporary; the body regains its original shape and size when the deforming force is removed. Plastic deformation is permanent; the body does not return to its original shape even after the force is removed. Elastic deformation occurs within the elastic limit, while plastic deformation occurs beyond the yield point.

Why is steel more elastic than rubber?

Steel is considered more elastic than rubber because it has a much larger Young's modulus. For the same stress, steel produces a much smaller strain compared to rubber. In physics, a material that stretches less for a given load is said to be more elastic.

What is Poisson's ratio and what are its typical values?

Poisson's ratio is the ratio of lateral strain to longitudinal strain when a material is stretched within its elastic limit. It is a dimensionless quantity. For steels, it is between 0.28 and 0.30, and for aluminium alloys, it is about 0.33.

How is elastic potential energy stored in a stretched wire?

When a wire is stretched, work is done against inter-atomic forces. This work is stored as elastic potential energy. The energy per unit volume is u = ½ × stress × strain. The total energy stored in a wire of volume V is U = ½ × stress × strain × V.

What does the stress-strain curve tell us about a material?

The stress-strain curve shows how a material deforms under increasing stress. It identifies the proportional limit (Hooke's law region), yield point (elastic limit), ultimate tensile strength, and fracture point. It also indicates whether a material is brittle (fractures soon after ultimate strength) or ductile (undergoes large plastic deformation before fracture).

Ready to master Mechanical Properties of Solids?

Get notes, topic quizzes, flashcards and an AI doubt solver for every Class 11 chapter. Free to start.

Create your free account