Class 12 Physics · Chapter 4 NotesMoving Charges and Magnetism
Revise Class 12 Physics Moving Charges and Magnetism with clear notes on Lorentz force, Biot-Savart law, Ampere's law, solenoids, torque and galvanometer.
Moving Charges and Magnetism explores how moving charges and electric currents create magnetic fields, and how those fields exert forces on other moving charges and current-carrying conductors. The chapter begins with Oersted's observation that a current-carrying wire deflects a nearby compass needle, establishing the link between electricity and magnetism. It then develops the Lorentz force, the motion of charged particles in magnetic fields, and the Biot-Savart law for calculating magnetic fields due to current elements. Ampere's circuital law provides a powerful alternative method for symmetric current distributions such as straight wires and solenoids. The chapter also covers the force between parallel currents, the torque on a current loop, the concept of magnetic dipole moment, and the working of the moving coil galvanometer. These ideas form the foundation for understanding devices like cyclotrons, ammeters, voltmeters and electromagnets.
What you'll learn
1Define the magnetic field and apply the Lorentz force expression F = q(E + v × B).
2Calculate the force on a current-carrying conductor placed in a magnetic field using F = I l × B.
3Analyse circular and helical motion of charged particles in uniform magnetic fields.
4Apply the Biot-Savart law to find magnetic fields due to current elements and circular loops.
5Use Ampere's circuital law to determine magnetic fields of straight wires and solenoids.
6Compute the force between two parallel current-carrying conductors.
7Determine the torque on a current loop and define magnetic dipole moment.
8Explain the principle and conversion of a moving coil galvanometer into an ammeter and voltmeter.
Chapter at a glance
01Magnetic Force on Moving Charges
02Motion of Charged Particles in Magnetic Field
03Magnetic Field due to Electric Current
04Ampere's Circuital Law and Applications
Detailed chapter notes
01
Magnetic Force on Moving Charges and Current-Carrying Conductors
A stationary charge produces an electric field, but a moving charge or current also produces a magnetic field. The total force on a charge q moving with velocity v in both electric field E and magnetic field B is called the Lorentz force: F = q(E + v × B). The magnetic part q(v × B) is always perpendicular to both v and B, so it does no work and cannot change the speed of the particle. The force is zero when the charge is at rest or when v is parallel or antiparallel to B. For a straight conductor of length l carrying current I in a uniform external field B, the force is F = I l × B, where the direction of l is along the current.
Lorentz forceF = q(E + v × B)
Magnetic force magnitudeF = q v B sin θ
Force on a conductorF = I l × B
Unit of magnetic fieldtesla (T); 1 gauss = 10⁻⁴ T
02
Motion of a Charged Particle in a Uniform Magnetic Field
When a charged particle moves perpendicular to a uniform magnetic field, the magnetic force acts as a centripetal force and the particle moves in a circle. Equating m v²/r to q v B gives the radius r = m v / (q B). The angular frequency is ω = q B / m, and the cyclotron frequency is ν = q B / (2π m), which is independent of speed and radius. If the velocity has a component along B, that component remains unchanged while the perpendicular component causes circular motion, resulting in a helical path. The distance moved along the field in one revolution is called the pitch, p = v∥ T = 2π m v∥ / (q B).
Radius of circular pathr = m v / (q B)
Cyclotron frequencyν = q B / (2π m)
Pitch of helixp = 2π m v∥ / (q B)
Magnetic force does no work; speed remains constant
03
Biot-Savart Law and Magnetic Field Due to a Circular Loop
The Biot-Savart law gives the magnetic field dB produced by a small current element I dl at a distance r: dB = (μ₀/4π) (I dl × r) / r³. Its magnitude is dB = (μ₀/4π) (I dl sin θ) / r², where θ is the angle between dl and r. The constant μ₀ is the permeability of free space, with μ₀/4π = 10⁻⁷ T m A⁻¹. Unlike the electric field, the magnetic field is perpendicular to the plane containing dl and r. For a circular loop of radius R carrying current I, the field on the axis at distance x from the centre is B = μ₀ I R² / [2 (x² + R²)^(3/2)]. At the centre (x = 0), B = μ₀ I / (2R).
Biot-Savart lawdB = (μ₀/4π) (I dl × r) / r³
μ₀ = 4π × 10⁻⁷ T m A⁻¹
Field at centre of circular loopB = μ₀ I / (2R)
Field on axisB = μ₀ I R² / [2 (x² + R²)^(3/2)]
04
Ampere's Circuital Law and Its Applications
Ampere's circuital law states that the line integral of B around a closed loop equals μ₀ times the total current enclosed: ∮ B · dl = μ₀ I. For symmetric cases, if B is tangential and constant along a path of length L, then B L = μ₀ Iₑ. Applying this to a long straight wire gives B = μ₀ I / (2π r) outside the wire. Inside a wire of radius a with uniform current density, B = (μ₀ I / 2π a²) r, so B ∝ r for r < a and B ∝ 1/r for r > a. For a long solenoid with n turns per unit length, the field inside is uniform: B = μ₀ n I.
Ampere's law∮ B · dl = μ₀ I
Long straight wireB = μ₀ I / (2π r)
Inside wire (r < a)B = (μ₀ I / 2π a²) r
Long solenoidB = μ₀ n I
05
Force Between Two Parallel Currents
Two long parallel conductors carrying currents Iₐ and I_b separated by distance d exert magnetic forces on each other. Conductor a produces a field Bₐ = μ₀ Iₐ / (2π d) at the location of conductor b. The force on a length L of conductor b is F_ba = μ₀ Iₐ I_b L / (2π d). The force per unit length is f = μ₀ Iₐ I_b / (2π d). Currents flowing in the same direction attract each other, while antiparallel currents repel. This is opposite to the behaviour of like electric charges. This force definition is used to define the ampere, the SI unit of current.
Ampere defined using force between two long parallel conductors
Newton's third law holds for steady currents
06
Torque on a Current Loop and Magnetic Dipole Moment
A rectangular loop of area A carrying current I in a uniform magnetic field B experiences no net force but a torque. The torque is τ = I A B sin θ, where θ is the angle between the normal to the loop and B. Defining the magnetic moment m = I A (direction given by the right-hand thumb rule), the torque is τ = m × B. For N turns, m = N I A. The torque is zero when m is parallel or antiparallel to B; parallel is stable equilibrium, antiparallel is unstable. A current loop behaves like a magnetic dipole at large distances, with field B = (μ₀/4π)(2m/x³) on the axis.
Torque on loopτ = m × B
Magnetic momentm = N I A
Unit of mA m²
Stable equilibrium when m is parallel to B
07
Moving Coil Galvanometer
A moving coil galvanometer detects and measures small currents. It consists of a coil of N turns suspended in a uniform radial magnetic field produced by a cylindrical soft iron core. When current I flows, the magnetic torque N I A B is balanced by the spring's restoring torque k φ, giving φ = (N A B / k) I. The current sensitivity is φ/I = N A B / k. To convert it into an ammeter, a small shunt resistance r_s is connected in parallel so most current bypasses the galvanometer. To convert it into a voltmeter, a large resistance R is connected in series to draw very little current.
Equilibriumk φ = N I A B
Current sensitivityφ/I = N A B / k
Ammetersmall shunt resistance in parallel
Voltmeterlarge resistance in series
Want the complete chapter resources?Topic notes, quizzes and flashcards for Moving Charges and Magnetism.
A charged particle moves perpendicular to a uniform magnetic field. What is the direction of the magnetic force acting on it?
AAlong the direction of velocity
BPerpendicular to both velocity and magnetic field
CAlong the magnetic field direction
DOpposite to the magnetic field direction
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Answer: (B) Perpendicular to both velocity and magnetic field
The magnetic force on a moving charged particle is given by F = q(v × B), which is always perpendicular to both the velocity and the magnetic field according to the cross product rule.
Question 02
When a charged particle moves perpendicular to a uniform magnetic field, the magnetic force acts as a centripetal force. What is the shape of the path traced by the particle?
ACircular path
BParabolic path
CElliptical path
DStraight line
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Answer: (A) Circular path
When a charged particle moves perpendicular to a magnetic field, the Lorentz force is always perpendicular to its velocity, causing it to move in a circular path with constant speed.
Question 03
The magnetic field due to a long straight current-carrying wire at a perpendicular distance r from the wire is given by which formula?
AB = μ₀I/(2πr)
BB = μ₀I/(4πr)
CB = μ₀I²/(2πr)
DB = μ₀I/(πr)
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Answer: (A) B = μ₀I/(2πr)
According to Biot-Savart law, the magnetic field at distance r from a long straight wire carrying current I is B = μ₀I/(2πr), where μ₀ is the permeability of free space.
Question 04
Ampere's circuital law relates the magnetic field around a closed loop to:
Athe electric charge enclosed
Bthe electric current passing through the loop
Cthe potential difference across the loop
Dthe resistivity of the conductor
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Answer: (B) the electric current passing through the loop
Ampere's circuital law states that the line integral of the magnetic field around a closed loop equals μ₀ times the current enclosed by that loop: ∮B·dl = μ₀I.
Question 05
The SI unit of magnetic field strength is:
ANewton per Coulomb
BTesla
CWeber per square meter
DAmpere per meter
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Answer: (B) Tesla
Tesla (T) is the SI unit of magnetic field strength (also called magnetic flux density). It can be derived as kg/(A·s²) or Newton/(Ampere·meter).
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Q1. State the Lorentz force on a charged particle moving in the presence of both electric and magnetic fields. Write the expression and explain why the magnetic force does no work.
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Model answer
The Lorentz force on a charge q moving with velocity v in electric field E and magnetic field B is F = q(E + v × B). The magnetic force q(v × B) is always perpendicular to the velocity v, so the dot product with displacement is zero. Hence, no work is done by the magnetic force; it only changes the direction of motion, not the kinetic energy.
Sample question3 marks
Q2. A charged particle enters a uniform magnetic field with its velocity perpendicular to the field. Derive an expression for the radius of its circular path.
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Model answer
When a charged particle moves perpendicular to a uniform magnetic field, the magnetic force provides the centripetal force: qvB = mv²/r. Solving for r gives r = mv/(qB).
Sample question3 marks
Q3. State Biot-Savart law and write its vector form.
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Model answer
Biot-Savart law states that the magnetic field dB due to a current element I dl at a point at distance r is proportional to I dl, inversely proportional to r², and depends on the angle between dl and r. Its vector form is dB = (μ₀/4π) (I dl × r) / r³.
Sample question3 marks
Q4. State Ampere's circuital law. Using it, derive the expression for the magnetic field at a distance r from an infinitely long straight current-carrying conductor.
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Model answer
Ampere's circuital law states that the line integral of the magnetic field B around any closed loop is equal to μ0 times the total current passing through the loop: ∮B·dl = μ0I. For an infinitely long straight wire carrying current I, consider a circular Amperian loop of radius r concentric with the wire. By symmetry, B is tangential and constant along the loop. Then ∮B·dl = B·2πr = μ0I, giving B = μ0I/(2πr).
Sample question3 marks
Q5. A charged particle enters a uniform magnetic field with its velocity perpendicular to the field. Derive an expression for the radius of its circular path.
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Model answer
When velocity v is perpendicular to magnetic field B, the magnetic force qvB acts as centripetal force. Equating: qvB = mv²/r. Solving for radius: r = mv/(qB). The radius is directly proportional to momentum and inversely proportional to charge and magnetic field.
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The Lorentz force is the total force on a charge q moving with velocity v in both electric field E and magnetic field B: F = q(E + v × B). The electric part qE can change the particle's speed, while the magnetic part q(v × B) is always perpendicular to v and does no work.
Why does a moving charge experience zero magnetic force when moving parallel to the magnetic field?
The magnetic force is F = q v B sin θ, where θ is the angle between v and B. When v is parallel or antiparallel to B, θ = 0° or 180°, so sin θ = 0 and the force is zero. The charge then moves undeflected along the field direction.
What is the difference between the Biot-Savart law and Ampere's circuital law?
The Biot-Savart law gives the magnetic field due to a small current element and is used by integrating over the entire conductor. Ampere's circuital law relates the line integral of B around a closed loop to the enclosed current and is easier for symmetric distributions like straight wires and solenoids.
How do you find the magnetic field inside a long solenoid?
For a long solenoid with n turns per unit length carrying current I, the field inside is uniform and given by B = μ₀ n I, directed along the axis. Outside an ideal long solenoid, the field is approximately zero.
Why do parallel currents attract each other?
A current-carrying conductor produces a magnetic field around it. Another parallel conductor placed in this field experiences a force. For currents in the same direction, the force is attractive; for opposite directions, it is repulsive. This is opposite to the behaviour of like electric charges.
How is a moving coil galvanometer converted into an ammeter and a voltmeter?
To convert a galvanometer into an ammeter, a small shunt resistance is connected in parallel so most current bypasses the coil. To convert it into a voltmeter, a large resistance is connected in series so it draws very little current and measures the voltage across a circuit section.